Length of the shadow of a 15 meter high pole is 15 root 3 meters at 7 o'clock in the morning. Then, what is the angle of elevation of the Sun rays with the ground at the time ?
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Answered by
94
Hey mate !!
Here's the answer !!
Let us take the scenario in the form of a right triangle, where the height of the pole is represented as AB, the shadow of the pole is represented as BC. Let
∠ C be the angle of Elevation.
So, We know that,
Tan Ф = Opposite / Adjacent
=> Tan Ф = 15 / 15 √ 3
=> Tan Ф = 1 / √ 3
We know that, Tan 30° = 1 / √ 3
So we can say that, Ф = 30°
Hence the angle of Elevation of the sum at that time was 30°.
Hope my answer helped !!
Cheers !!
Here's the answer !!
Let us take the scenario in the form of a right triangle, where the height of the pole is represented as AB, the shadow of the pole is represented as BC. Let
∠ C be the angle of Elevation.
So, We know that,
Tan Ф = Opposite / Adjacent
=> Tan Ф = 15 / 15 √ 3
=> Tan Ф = 1 / √ 3
We know that, Tan 30° = 1 / √ 3
So we can say that, Ф = 30°
Hence the angle of Elevation of the sum at that time was 30°.
Hope my answer helped !!
Cheers !!
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HPMakers30:
thanks bro
Answered by
45
angle of elevation of the sun rays with the ground at the time is 30°
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