Length of the shadow of a 20 meter high pole is 20 meter at 7:30 degree am. The angle of elevation of the sun rays with the ground ?
(A) 30 degree
(B) 45degree
(C) 60 degree
(D) 90 degree
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I assume the tree is perpendicular to the ground. So we have a simple right triangle with one angle 23.5 deg with opposite side of 20 m. Using Tangent23.5, I calculate the ratio of that side to the shadow (Tan is opposite/adjacent).
So 20/0.435=46m
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