Question

Length of the shadow of a tree is equal to height of the tree at 10 o clock in morning then can u find angle of elevation of Sunrays with ground explain

Answer 1

Answer:

angle of elevation= 45

AB=BC

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Answer 2

Angle of elevation of sunrays with ground is = 45°

Step-by-step explanation:

From the Δ ABC

AB = Height of the tree = h

BC = Shadow of the tree

Length of the shadow of a tree is equal to height of the tree.

AB = BC = h

From pythagoras theorm

$AC^{2} = AB^{2} + BC^{2}$

$AC^{2} = h^{2} + h^{2}$

$AC^{2} = 2h^{2}$

AC = $\sqrt{2} h$

From Triangle ABC  

$\sin \theta = \frac{AB}{AC}$

$\sin \theta = \frac{h}{\sqrt{2} h}$

$\sin \theta = \frac{1}{\sqrt{2} }$

⇒ $\theta = 45$°

Therefore,  angle of elevation of Sunrays with ground is = 45°