length of the sides PQ,QR,PR
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QR + RP + PQ= 1/2× (AB+BC+CA)
=> QR+RP+PQ= 1/2 × (12 + 15 + 10)
= 1/2 × 37
= 18.5
this is the perimeter of the inner triangle.
now ,
QR= 1/2 AB= 1/2 × 12=6
RP=1/2 BC= 1/2 × 15 = 7.5
PQ= 1/2 CA = 1/2 × 10 = 5
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=> QR+RP+PQ= 1/2 × (12 + 15 + 10)
= 1/2 × 37
= 18.5
this is the perimeter of the inner triangle.
now ,
QR= 1/2 AB= 1/2 × 12=6
RP=1/2 BC= 1/2 × 15 = 7.5
PQ= 1/2 CA = 1/2 × 10 = 5
HOPE IT WILL HELP YOU. . . . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! ! !
HridayAgrawal:
Plz mark my answer as brainliest as soon as possible whenever the option appears
k bro bt it ws not a dificult it ws as easy as 4 ka table
But then too
I have given u whatever u asked
and in which class u are??
bro i ws checking the app is good or not fr my younger brother i m persuing graduation
bt i will do wht u hv askd bt option ni a rha h
in which standard ur brother study in?
wo ek week baad ayega
8 bhaii ok turant kr dunga pkka
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