Question

Length of the simple pendulum is 25 cm and time of 40 oscillation is 50 second.if resolution of stop watch 1 second then accuracy is g (in %)

Answer 1

Thus the accuracy in g in percentage is 4.4%

Explanation:

Given data:

• Length of simple pendulum = 25 cm
• Number of oscillations = 40
• Time of oscillations = 50 seconds
• Percentage accuracy = ?

Solution:

ΔT / T = 1/2 (Δg / g + ΔL / L)

Δg / g = 2ΔT / T + ΔL / L

Δg / g = 2 x 1 / 50 + 0.1 / 25 = 1/25 + 0.1 / 25

Δg / g = 1.2 / 25 = 4.4 %

Thus the accuracy in g in percentage is 4.4%