Question

length of the two parallel sides of a Trapezium are 8.5 CM and 11.5 CM Respectively and it's height is 4.2 CM, find it's area​

Answer 1

Given :–

• Parallel sides = 8.5cm and 11.5cm
• Height = 4.2cm

To Find :–

• Area of a trapezium.

Solution :–

We know that,

Area of a trapezium = $\dfrac{1}{2}$ × (sum of two parallel sides) × height

• Sum of two parallel sides = 8.5cm + 11.5cm
• Height = 4.2cm

Now, put the given values on the formula of area of a trapezium.

⟹ $\dfrac{1}{2}$ × (8.5 + 11.5) × 4.2

⟹ $\dfrac{1}{2}$ × (20) × 4.2

⟹ $\dfrac{1}{\cancel2} \times \cancel{20}$ × 4.2

⟹ 10 × 4.2

⟹ $\cancel{10}$ × $\dfrac{42}{\cancel{10}}$

⟹ 42cm²

Hence,

The area of a trapezium is 42cm².

Answer 2

Given ,

• The parallel sides of trapezium are 8.5 cm and 11.5 cm

• Height of trapezium is 4.2 cm

We know that , the area of trapezium is given by

$\boxed{ \sf{Area = \frac{1}{2} \times (Sum \: of \: parallel \: sides) \times Height }}$

Thus ,

Area = 1/2 × (8.5 + 11.5) × 4.2

Area = 1/2 × 20 × 4.2

Area = 10 × 4.2

Area = 42 cm²

Therefore ,

• The area of trapezium is 42 cm²