Question

length of the vector 2i+3j+4k in the xy plane

Answer 1

theanswer is 5j+4k. it's simple.

Answer 2

The question is we have to find the length of the vector 2i+3J+4K

The vector in XY plane will be i and j

The vector will have both magnitude and direction.

If w calculate the magnitude we may get a length of a vector.

The magnitude of a XY plane will be

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ magnitude==$\sqrt{x^{2} +y^{2} }$

in xy plane the value of plane z will be zero.

so,we have only x and y,which is i and j vector.$\sqrt{2^{2} +3^{2} }$

$\sqrt{4+9}$

Therefore the final answer is$\sqrt{13}$.

#spj3