Length of wire is 60m and it is used to enclose a right angled triangle with area 150m square then what is the largest side of the field has a length of
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let us assume p,q,r as lengths of the given triangle sides.let right angle is in between sides p,q and r is hypotenuse(largest side).
using pythagoras theorem
p^2+q^2=r^2 ----->eq.1
as circumference=60
p+q+r=60 -------> eq.2
area=(1/2)*p*q=150 ------->eq.3
we can write 2nd eq. as
(p+q)=(60-r)
squaring on both sides
p^2+q^2+2*p*q=3600+r^2-120*r ------->eq.4
by substituting eq. 1and 3 in 4
r^2+600=3600+r^2-120*r
on solving we get
r=25(largest s
using pythagoras theorem
p^2+q^2=r^2 ----->eq.1
as circumference=60
p+q+r=60 -------> eq.2
area=(1/2)*p*q=150 ------->eq.3
we can write 2nd eq. as
(p+q)=(60-r)
squaring on both sides
p^2+q^2+2*p*q=3600+r^2-120*r ------->eq.4
by substituting eq. 1and 3 in 4
r^2+600=3600+r^2-120*r
on solving we get
r=25(largest s
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