Question

lengths of diagonal of the OK m bus ABCD are 16 CM and 12 CM. find the side and perimeter of the rhombus​

Answer 1

Answer:

Step-by-step explanation:

Since the diagonals of rhombus bisect each other a right angled triangle with sides 8 , 6 and A is formed where A is side of rhombus.

Solving we get A=10, so we got a side.

Perimeter of rhombus=4A

=4*10

=40

Answer 2

Answer:

First take the point of intersection of the 2 diagonals be point O

Then, in triangle ABO,

OB=1/2 OF DB

= 6cm

OA=1/2 OF AC

= 8cm

So, by using pythagoras theorem,

AB^2 = OA^2 + OB^2

AB^2 = 8^2 + 6^2

AB^2 = 64 + 36

AB^2 = 100

AB = √100

Therefore Side AB of the rhombus ABCD = 10cm= All sides of rhombus

Perimeter = 4a = 4*10 = 40cm