Question

Lengths of diagonals of a rhombus are 21 cm. and 24 cm.find it's area.​

Answer 1

Step-by-step explanation:

Here, the diagonals are

$p = 21cm \: \\ and \: q = 24 \: cm$

therefore,

$area \: of \: rhombus$

$= \frac{pq}{2}$

$= \frac{21 \times 24}{2}$

$= 252 {cm}^{2}$

this is the required answer...

hope it help u...

Answer 2

Let the rhombus is ABCD, given that :

AC=24cm and BD=18cm.

Let the Diagonal of Rhombus bisect each other at right angles.

AO=OC= 12

and OB = OD =9 cm

Let ∠AOD=90

∘

In right ΔAOD,

AO= 12 cm and OD=9 cm

Using phythagoras theorem,

AD square= AO square+OD square

AD square= 12 ×12+9×9

AD square= 144+81

AD square= 225

AD = √225

AD=15 cm

Hence the all side of rhombus are equal

Hence the each side of the rhombus is 15cm.