Question

lengths of the diagonal of a rhombus are 16.5cm and 14.2cm , find its area ​

Answer 1

$\huge\mathbb{\underline{SOLUTION:-}}$

$\begin{cases}\sf{Diagonal_1\:of\: Rhombus=16.5cm}\\ \sf{Diagonal_2\:of\: Rhombus=14.2}\end{cases}$

$\boxed{\sf{Area\:of\: Rhombus=\frac{1}{2}\times (product\:of\: diagonals)}}$

• NOW FIND THE AREA OF RHOMBUS

$\bf\underline{\underline{According\:To\: Question:-}}$

$\sf\implies Area=\frac{1}{2}\times 16.5\times 14.2\\ \\ \sf\implies Area=\frac{1}{\cancel2}\times 16.5\times \cancel{14.2}\\ \\ \sf\implies Area=16.5\times 7.1\\ \\ \sf\implies Area=117.15cm{}^{2}$

$\boxed{\mathfrak{\purple{Area\:of\: rhombus=117.15cm{}^{2}}}}$

#BAL

#answerwithquality

Answer 2

$\underline \mathbb{SOLUTION}$

》$\underline \mathbb{GIVEN}$

DIAGONAL OF RHOMBUS= 16.5 cm

2nd DIAGONAL OF RHOMBUS=14.2

$= > area \: of \: rhombus = \frac{1}{2} \times (product \: of \: diagonals)$

$\underline \mathbb{TO\:FIND}$

》AREA OF RHOMBUS

$\underline \mathbb{ATQ}$

$= > area = \frac{1}{2} \times 16.5 \times 14.2$

$= > area = 16.5 \times 7.1$

$= > area = 117.15 {cm}^{2}$

$\underline \mathbb{ANSWER}$

AREA OF RHOMBUS = 117.15 square cm.

_______________________________________

#BAL

#Answerwithquality