Lenier Equation- A man is twice as old as his son. Twelve years ago, the man was thrice as old as his son. Find thier present ages.
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x: the father’s age today y: the son’s age
“the man is twice as old as his son”: x = 2y
“twelve years ago, he was thrice as old as his son”: x-12 = 3*(y-12)
so 2y-12 = 3*(y-12)
In the end, you find y=24 and x=12, so today the father is 48 years old and his son is 24 years old I hope it helps you
“the man is twice as old as his son”: x = 2y
“twelve years ago, he was thrice as old as his son”: x-12 = 3*(y-12)
so 2y-12 = 3*(y-12)
In the end, you find y=24 and x=12, so today the father is 48 years old and his son is 24 years old I hope it helps you
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