Question

Lenses of power is+20and-20and put together it's focal length is

Answer 1

Answer:

0

Explanation:P= 1/f

So

f(1)= 1/20m

And

f(2)=-1/20m

f(effective) = f(1)+f(2)

= 0

Answer 2

Answer:

0

Explanation:P= 1/f

So

f(1)= 1/20m

And

f(2)=-1/20m

f(effective) = f(1)+f(2)

= 0

Explanation:pls not ez for me to this so my bro help me