Question

Lesch nyhan disease is an x linked recessive disorder that causes neurological damage in human beings a survey of 500 mates from a caucasion population revealed that 20 were affected with this disease find the frequency

Answer 1

Answer:

survey of population= 500

population affected= 20

therefore frequency= 20/500 *100%

= 4% (answer)

Hope you will be able to understand.

Answer 2

Answer:

$Hello Dear,</p><p></p><p>● Answer -</p><p></p><p>Frequency of normal allele = 0.8</p><p></p><p>◆ Explaination -</p><p></p><p>Let p be frequency of dominant (normal) allele & q be frequency of recessive (defective) allele.</p><p></p><p>According to Hardy-Weinberg principle,</p><p></p><p>p² + 2pq + q² = 1</p><p></p><p>Given that affected people (homozygous recessive) are 20 in 500 observations.</p><p></p><p>q² = 20 / 500</p><p></p><p>q² = 0.04</p><p></p><p>q = 0.2</p><p></p><p>Putting this in eqn,</p><p></p><p>p² + 2pq + q² = 1</p><p></p><p>p² + 2p × 0.2 + 0.04 = 1</p><p></p><p>p = 0.8</p><p></p><p>Hence, frequency of normal (dominant) allele w.r.t. Lesch–Nyhan syndrome in given population is 0.8 .</p><p></p><p>$