Lesch-nyhan syndrome is an x- linked recessive disorder that cause neurological damage in human beings. A survey of 500 males from a population revealed that 20 were affected with this disorder. What will be the frequency of the normal allele in the population?
Answers
Hello Dear,
● Answer -
Frequency of normal allele = 0.8
◆ Explaination -
Let p be frequency of dominant (normal) allele & q be frequency of recessive (defective) allele.
According to Hardy-Weinberg principle,
p² + 2pq + q² = 1
Given that affected people (homozygous recessive) are 20 in 500 observations.
q² = 20 / 500
q² = 0.04
q = 0.2
Putting this in eqn,
p² + 2pq + q² = 1
p² + 2p × 0.2 + 0.04 = 1
p = 0.8
Hence, frequency of normal (dominant) allele w.r.t. Lesch–Nyhan syndrome in given population is 0.8 .
Hope I was useful.
Hello Dear,
● Answer -
Frequency of normal allele = 0.8
◆ Explaination -
Let p be frequency of dominant (normal) allele & q be frequency of recessive (defective) allele.
According to Hardy-Weinberg principle,
p² + 2pq + q² = 1 ...(1)
Given that affected people (homozygous recessive) are 20 in 500 observations.
q² = 20 / 500
q² = 0.04
q = 0.2
Putting this in eqn,
p² + 2pq + q² = 1
p² + 2p × 0.2 + 0.04 = 1
p = 0.8
Hence, frequency of normal (dominant) allele w.r.t. Lesch–Nyhan syndrome in given population is 0.8 .
Hope I was useful.