Math, asked by officialanubrata14, 1 month ago

Lesle sold her tow bikes, one at 10% loss and the other at 20% profit. Find her overall profit percentage if she sold both the bikes at the same price.
A. 2.857%
B. 2.625%
C. 2.425%
D. 1.687%​​

Answers

Answered by Swarup1998
0

To find:

Overall profit percentage if she sold both the bikes at the same price

Step-by-step explanation:

Let the selling price of each bike is x

The first bike was sold at 10% loss.

Then its cost price

= x/(1 - 10/100)

= x/(90/100)

= 100x/90

= 10x/9

The second price was sold at 20% profit.

Then its cost price

= x/(1 + 20/100)

= x/(120/100)

= 100x/120

= 5x/6

Since it is mentioned that the selling was a profit, then profit

= (x + x) - (10x/9 + 5x/6)

= 2x - (20x + 15x)/18

= 2x - 35x/18

= (36x - 35x)/18

= x/18

Total cost price of the two bikes

= 10x/9 + 5x/6

= 35x/18

Hence profit percentage

= total profit / total cost price * 100 %

= (x/18) / (35x/18) * 100 %

= 1/35 * 100 %

= 2.857 %

Final answer: A. 2.857%

Her overall profit percentage be 2.857% if she sold both the bikes at the same price.

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Answered by Anonymous
0

Given:

Total num er of bikes = 2

Loss at which bike is sold = 10%

Profit at which bike is sold = 20%

To Find:

Overall profit percentage if both the bikes were sold at the same price.

Solution:

Let the CP of first bike be  = 100x

Let the CP of second bike = 100y

Therefore,

CP = 100x + 100y

Sold at 10 % loss

= 10/100 x 100x

= 10x

Thus, SP = 100x - 10x

= 90x

Sold at 20 % profit

= 20/100 x 100y

= 20y

SP = 100y + 20y  

= 120y

Now 90x = 120y

Total SP = 90x  + 120y   =  180x

Now,

CP = 100x + 100y  

Substituting value -

= 100x + 100(3x/4)

= 175x

Profit = 180x - 175x  

= 5x  

Profit %

= 5x/175x x 100  

= 2.857 %

Answer: The overall profit is A. 2.857%

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