less than 5 10 15 20 25 30 35
Answers
Answer:
1,2,3,4
Explanation:
Answer:
µ =
n
∑
i = 0
Xi
n
Input parameters & values
x1 = 5; x2 = 10, . . . . , x10 = 50
number of elements n = 10
Find sample or population mean for 5, 10, 15, 20, 25, 30, 35, 40, 45 & 50
step 2 Find the sum for dataset 5, 10, 15, 20, 25, . . . . , 45 & 50
µ =
n
∑
i = 0
Xi
n
=(5 + 10 + 15 + . . . . + 50)
10
step 3 Divide the sum by number of elements of sample or population
=275
10
= 27.5
Mean (5, 10, 15, 20, 25, . . . . , 45, 50) = 27.5
27.5 is the mean for dataset 5, 10, 15, 20, 25, . . . . , 45 & 50 from which the standard deviation about to be measured to estimate the common variation of the sample or population dataset from its central location.
Median :
step 1 To find Median, arrange the data set values in ascending order
Data set in ascending order : 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
step 2Since the total number of elements in the dataset is 10 (EVEN number), the median is the average of 5th and 6th elements (two middle numbers) for the above dataset.
Therefore,
25 + 30
2
= 27.5
Median = 27.5
Mode :
step 1 To find Mode, check for maximum repeated elements in the asending ordered dataset 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
No mode available for the above dataset