Computer Science, asked by deepeshsarsar44, 5 months ago

less than cumlavtive frequency of marks obtained by 100 students in statistics for the class interval 50-60 is 55 then we can conclude that​

Answers

Answered by surajdewanshu502
1

Answer:

60

Explanation:

100 minutes per HR no

Answered by smithasijotsl
0

Answer:

We can conclude that the 50 - 60 is the median class and the median of the data lies between 50 and 60.

Explanation:

Given,

No of students  = 100

cumulative frequency of the marks obtained by 100 for the class interval 50-60 is 55.

In a frequency distribution, the median class is that class in which the cumulative frequency is just greater than \frac{N}{2}, where N is the total frequency

Here, N = total frequency = 100

\frac{N}{2} = 50

Given that, the less than the cumulative frequency of the class interval

50 - 60  is 55.

Hence we can conclude that the 50 - 60 is the median class

and the median of the data lies between 50 and 60.

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