Math, asked by thandapani, 1 year ago

lesson name is problems on time and work
1)'A'can do a work in 10 days and 'B' can do the same work in 16 days . with the help of C ,they do the work in 4 days only.in how many days 'C' can do the work alone?
answer = 11 × 3/7 days

Answers

Answered by amankumargiri020
0

Answer:

THIS IS THE EXPLANATION

Step-by-step explanation:

A's one day work= 1/10

B's one day work= 1/20

Let C's one day work=1/x

(A+B+C)'s one day work= 1/10 + 1/20 + 1/x

But it's given that they complete the work in 4 days. Hence their one day work will be 1/4

Therefore, (1/10 + 1/20 + 1/x) = 1/4

Solving for x, we get x = 10

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