Question

lesson no 15 Area std 8th maharashtra board​

Answer 1

Step-by-step explanation:

area of ABCDEF = ar(APF)+ar(ABSP)+ar(SBC)+ar(RDC)+ar(QRDE)+ar(FQE)

ar of APF = 1/2×b×h

1/2×30×50=15×50=750

ar of APBS = l×b

(50+70+10)×50=130×50=6500

ar of SBC = 1/2×b×h

1/2×50×30=15×50=750

ar of RDC =1/2×b×h

1/2×(10+30)×40=1/2×40×40=40×20=800

ar of QRDE (trapezium) = 1/2(sum of parallel sides )×height

1/2(40+60)×70=1/2×100×70=35×100=3500

ar of FQE= 1/2×b×h

1/2×(30+50)×60=1/2×80×60=40×60=2400

Ar of ABCDEF= 750+6500+750+800+3500+2400=14700 m^2

Please mark this as brainlist