Let = {(1,1), (2,3), (0, −1), (−1, −3) … } be a function from Z to Z defined by () = + ,
for some integers and . Determine and .
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Answer:
f={(1,1),(2,3),(0,−1),(−1,−3)}
f(x)=ax+b
(1,1)∈f
⇒f(1)=1
⇒a×1+b=1
⇒a+b=1 .....(1)
(0,−1)∈f
⇒f(0)=−1
⇒a×0+b=−1
⇒b=−1
On substituting b=−1 in eqn (1), we get
a+(−1)=1
⇒a=1+1=2
Thus the respective values of a and b are 2 and −1
Step-by-step explanation:
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