Let { 1,2,3,4,5,6} , B: {3,4,5} then find the number of subsets of A (i)disjoint from B (ii) having exactly one element of B. (iii) having exactly two element of B (iv) subsets of A and subersets of B
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Answer:
41
Given, S={1,2,3,4}
Each element can be put in 3 ways either in subsets or we don't put in any subset.
Total number of unordered pairs of disjoint subsets,
=
2
3
n
+1
=
2
3
4
+1
=41
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