let 10^101-1 be expressed as an integer in the standard form. what is the sum of the digits of this integer
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I dont Know the answer sorry
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If we will perform this operation we will be having 1with 102 zeroes afte it ,afrer substracting 1 we will have 102times 9 . For sum of the digits we will add 9 102 times... i.e, 9*102 that is 918. And that's the answer.
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