let 2uc and 4uc are separated by a distance 4m in air then a dielectric slab of thickness 1m and dielectric constant 4 is introduced between them then find force of repulsion between them.
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1uc = 10^-6c
2uc = 2x10^-6c
4uc = 4x10^-6c
d=4 x=1 k=4
f= 1/4(pi)e0 x q1 q2 /9(d-x)+k^1/2.x)^2
f=9x10^9x2x10^-6x4x10^-6(3+2)^2
f=72x0.04x10^-3
f=2.88x10^-3 N
2uc = 2x10^-6c
4uc = 4x10^-6c
d=4 x=1 k=4
f= 1/4(pi)e0 x q1 q2 /9(d-x)+k^1/2.x)^2
f=9x10^9x2x10^-6x4x10^-6(3+2)^2
f=72x0.04x10^-3
f=2.88x10^-3 N
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ibrahimak:
thank you
Will you please write formula clearly
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