Question

Let 5 ​ be a rational number. then it must be in form of q p ​ where, q  ​ =0 ( p and q are co-prime) 5 ​ = q p ​ 5 ​ ×q=p Suaring on both sides, 5q 2 =p 2 --------------(1) p 2 is divisible by 5. So, p is divisible by 5. p=5c Suaring on both sides, p 2 =25c 2 --------------(2) Put p 2 in eqn.(1) 5q 2 =25(c) 2 q 2 =5c 2 So, q is divisible by 5. . Thus p and q have a common factor of 5. So, there is a contradiction as per our assumption. We have assumed p and q are co-prime but here they a common factor of 5. The above statement contradicts our assumption. Therefore, 5 ​ is an irrational number.

Answer 1

Answer:

Two integers p and q are said to be r coprime (also written co-prime) if the only positive integer (factor) that divides both of them is 1

So according to this they both have only one common factor that is 1 so HCF =1

Correct answer will be Option D

please mark my answer as brainliest answer please my dear friend

Answer 2

Answer:

yes✅✅

Step-by-step explanation:

why not brother