Let A= {0, 1, 2, 3, 4, 5}, B= {2, 4, 6, 8} and C= {1, 3, 5, 7} . Verify (A ∩ B) ∩ C = A ∩ (B ∩ C)
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First, we find A ∪ (B ∩ C),
Consider B ∩ C= {2, 4, 6, 8} ∩ {1, 3, 5, 7}
= Ф
(this above sign means that nothing is common and called 'fi')
⇒ A ∩ (B ∩ C) = {0, 1, 2, 3, 4, 5} ∩ Ф
= Ф ..(1)
Next, consider A ∩ B = {0, 1, 2, 3, 4, 5} ∩ { 2, 4, 6, 8}
= { 2, 4,}
(A ∩ B) ∩ C = {1, 3, 5, 7} ∩ {2, 4}
= Ф ...(2)
Thus,
From (1) and (2), we get
A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
hence proved..
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