Let a ∈ (0,∞)/[1], then show that logₐᵃ+ log ₐᵃ³+log ₐᵃ⁵+.........+log ₐᵃ²⁻¹=n²
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i hope this will usful to u
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Answered by
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Step-by-step explanation:
1+3+5+...+2n-1
sum of odd no = n²
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