Question

let A(1 1 2 ) ( 2 2 1 ) (2 1 2 ) then trace of A^3 is​

Answer 1

Answer:

I think b is the correct ans

Step-by-step explanation:

100 is it

Answer 2

Answer:

A(1 1 2 ) ( 2 2 1 ) (2 1 2 )  then trace of A^3  is​ 101

Step-by-step explanation:

A =$\left[\begin{array}{ccc}1&1&2\\2&2&1\\2&1&2\end{array}\right]$

A^2 = $\left[\begin{array}{ccc}1&1&2\\2&2&1\\2&1&2\end{array}\right]$   *  $\left[\begin{array}{ccc}1&1&2\\2&2&1\\2&1&2\end{array}\right]$

A^2 = $\left[\begin{array}{ccc}7&5&7\\8&7&8\\8&6&9\end{array}\right]$

Then A^3 = A^2 * A

A^3 = $\left[\begin{array}{ccc}7&5&7\\8&7&8\\8&6&9\end{array}\right]$  *  $\left[\begin{array}{ccc}1&1&2\\2&2&1\\2&1&2\end{array}\right]$

  A^3 =  $\left[\begin{array}{ccc}31&24&33\\38&30&39\\38&29&40\ \end{array}\right]$

The trace of a matrix is the sum of the diagonal elements of the matrix: The trace is sometimes called the spur.

trace of A^3 is = 31+30+40 = 101

Therefore trace of A^3 is 101.