Question

let a=(1,-1) b=(a,b,c) then number of possible relations from ato b is a)16 (b) 64 (c)7 (d) 81
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Answer 1

→  a×b  =  {(a,1),(a,-1),(b,1),(b,-1),(c,1),(c,-1)}

∵ n(A×B)=6

→  The number of subsets of A×B is $2^{6}$  =  64

→  So, (b) 64 is the right option.■

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