let A={1,2,3...14}. define the relation r from a to a by r={(x,y):3x-y=1,where x, yea}. write down its domain , co-domain and range
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Answered by
28
By definition of the relation,
R = {(1, 3), (2, 6), (3, 9), (4, 12)}
The set of first element, i.e. the domain = {1, 2, 3, 4}
Similarly, the set of second elements, i.e. the range = {3, 6, 9, 12}
And the co-domain = {1, 2, 3, ….. 14}
R = {(1, 3), (2, 6), (3, 9), (4, 12)}
The set of first element, i.e. the domain = {1, 2, 3, 4}
Similarly, the set of second elements, i.e. the range = {3, 6, 9, 12}
And the co-domain = {1, 2, 3, ….. 14}
Answered by
111
It is given that the relation R from A to A is given by R = {(x, y): 3x – y = 0, where x, y ∈ A}.
It means that R = {(x, y) : 3x = y, where x, y ∈ A}
Hence, R = {(1, 3), (2, 6), (3, 9), (4, 12)}
We know that the domain of R is defined as the set of all first elements of the ordered pairs in the given relation.
Hence, the domain of R = {1, 2, 3, 4}
To determine the codomain, we know that the entire set A is the codomain of the relation R.
Therefore, the codomain of R = A = {1, 2, 3,…,14}
As it is known that, the range of R is defined as the set of all second elements in the relation ordered pair.
Hence, the Range of R is given by = {3, 6, 9, 12}
Hope it's Helpful.....:)
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