Let A = {1,2,3,4,5,6) and R be the relation defined on A by R= {(x, y): x,y e A,x divides y), then range of R is
Answers
Step-by-step explanation:
Given :-
Let A = {1,2,3,4,5,6) and R be the relation defined on A by R= {(x, y): x,y € A, x divides y)}
To find :-
Find the range of R ?
Solution :-
Given set is A = { 1,2,3,4,5,6}
Given relation = R
R is defined by {(x, y): x,y € A,x divides y)}
1 divides 1 then the order pair = (1,1)
1 divides 2 then the order pair = (1,2)
1 divides 3 then the order pair = (1,3)
1 divides 4 then the order pair = (1,4)
1 divides 5 then the order pair = (1,5)
1 divides 6 then the order pair = (1,6)
2 divides 4 then the order pair = (2,4)
2 divides 6 then the order pair = (2,6)
3 divides 6 then the order pair = (3,6)
So R = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,4),(2,6),(3,6) }
The set of first elements in the order pair of R
= { 1,2,3)
Domain of R = {1,2,3}
The set of second elements in the order pair of R
= { 1,2,3,4,5,6}
Range of R = { 1,2,3,4,5,6}
Answer:-
The range of R for the given problem is {1,2,3,4,5,6}
Used formulae:-
- The set of first elements in an ordered pair is called the Domain .
- The set of second elements in an ordered pair is called the Range .
- 1 divides every number .
- 1 is the factor of every number.