Let A = {1, 2, 3, 4, 5} B = {1, 3, 5} C = {4, 6}. Find
n(A) ,n(B) ,n(A ⋃ C) and n(A ⋂ C)7
Answers
Answered by
1
Answer:
n(A) = {1,2,3,4,5}
n(B) = {1,3,5}
n(A U C) = {1,2,3,4,5,6}
n(A intersection C) = {1,2,3,5}
Answered by
7
Solution:
- For finding n(A):
n(A) represents the number of terms present in set A.
Here, in set A there are 5 terms.
So n(A) = 5
- For finding n(B):
n(B) represents the number of terms in set B.
There are 3 terms in B.
So, n(B) = 3
- For finding n(A U C):
n(A U C) represents the number of terms in (A U C).
A U C is the set which includes all terms of A and C but the elements should not be repeated.
A U C = {1, 2, 3, 4, 5, 6}
There are 6 terms.
So, n (A U C) = 6
- For finding n(A ⋂ C):
A ⋂ C includes terms which are present both in A and C.
A ⋂ C = {4}
Here A ⋂ C contains only 1 element.
So, n(A ⋂ C) = 1
Similar questions