let a={1,2,3,4,5}. construct a relation of not reflexive, symmetric,transitive
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(i) we define a relation R
1
as
R
1
={(1,1),(2,2),(3,3),(4,4),(1,2),(2,3),(1,3)}
Then it is easy to check that R
1
is reflexive, transitive but not symmetric. Students are advised to write other relations of this type.
(ii) Define R
2
as: R
2
={(1,2),(2,1)}
Ti is clear that R
2
is symmetric but neither reflexive nor transitive. Write other relations of this type.
(iii) We define r
3
as follows:
R
3
={(1,1),(2,2),(3,3),(4,4),(1,2),(2,1)}.
Then evidently R
3
is reflexive, symmetric and transitive, that is, R
3
is an equivalence relation on A.
(1, 2) ∈R
3
,(2,1)∈R
3
⇒(1,1)∈R
3
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