Math, asked by aksharabiju456234, 10 months ago

Let A {1, 2, 3, 4, 5}, let R be the relation defined on A by
R= {(a, b) abEA and a divades b}. Test whether Ris reflexive,
Symmetric and transitive​

Answers

Answered by shadowsabers03
5

The relation R is defined on the set A=\{1,\ 2,\ 3,\ 4,\ 5\} as,

\longrightarrow R=\{(a,\ b):a,\,b\in A,\ a\mid b\}

Hence R in roster form will be,

\begin{aligned}\longrightarrow R\ =\ \ \{&(1,\ 1),\ (1,\ 2),\ (1,\ 3),\ (1,\ 4),\ (1,\ 5),\\&(2,\ 2),\ (2,\ 4),\ (3,\ 3),\ (4,\ 4),\ (5,\ 5)\}\end{aligned}

Here (1,\ 1),\,(2,\ 2),\,(3,\ 3),\,(4,\ 4),\,(5,\ 5)\in R. Hence R is reflexive.

Here (1,\ 2)\in R but (2,\ 1)\notin R. Hence R is not symmetric.

Here, (1,\ 2),\,(2,\ 4)\in R and so (1,\ 4)\in R. Hence R is transitive.

Therefore, R is reflexive and transitive but not symmetric.

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