Question

Let A = {1,2,3,4},B = {2,4,6}. Then the member of sets C such that ABCCSA Bis
A) 8
B) 4
C) 10
D) 12​

Answer 1

Answer:

M=(A intersection B)={2,4} and N=(A union B)={1,2,3,4,6}

Now, it is given that C is a superset of M and a subset of N. Considering this we have 3 cases.

Set C contains only two elements, that is C={2,4}. Only one such case is possible

Set C contains 3 elememts , that is C={2,4,x} where x can be 1,3 or 6. Therefore there are 3 cases

Set C contains 4 elements,that is C={2,4,x,y}. The possible combinations of x and y are {(1,3);(1,6);(3,6)} Therefore three such cases

Set C contains all 5 elements. Only one such case exists

Now if you add them all up, you get 8, so 8 must be the answer.

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Step-by-step explanation:

Answer 2

Answer:

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