let a=(1,2,3) b=(2,3,4) then n(a×b) intersection (b×a)
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Answer:
option: (c) 4
Step-by-step explanation:
A = {1,2,3} , B = {2,3,4}
Now,
AxB = {1,2,3} x {2,3,4}
= {(1,2),(1,3),(1,4),(2,2),(2,3),(2,4),(3,2),(3,3),(3,4)}
and
BxA = {2,3,4} x {1,2,3}
= {(2,1),(2,2),(2,3),(3,1),(3,2),(3,3),(4,1),(4,2),(4,3)}
A/Q,
(AxB)&(BxA) = {(2,2),(2,3),(3,2),(3,3)}
so,
n(AxB)&(BxA) = 4.
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