Let A = {1, 2 }, B = {3, 4} . Find n(P(A X B))
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Answer:
n(A×B) =4
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Step-by-step explanation:
Given :-
A = {1, 2 },
B = {3, 4}
To find :-
Find n(P(A X B)) ?
Solution :-
Given sets are :
A = {1, 2 }
B = {3, 4}
A X B = { 1, 2 } X { 3, 4 }
=> A X B = { (1,3),(1,4),(2,3),(2,4) }
Number of elements in A X B = 4
n (A X B ) = 4
We know that
The number of subsets of a set of 'n' elements is 2^n
We have, n = 4
So, The number of subsets of A X B = 2^4
=> 2×2×2×2
=> 16
We know that
The number of sub sets of a set A =n( P(A))
The number of subsets of the set A X B
= n(P(A X B)) = 16
Answer:-
The value of n(P(A X B)) for the given problem is 16
Used formulae:-
Let A and B are two non empty sets,
- The set containing order pairs such that first element belongs to A and second element belongs to B is called the Cartesian product of the sets A and B.
- A X B = {(a,b)/ a€ A , b € B}
- € = belongs to
- The number of elements in a set A is called the Cardinal number of A and it is denoted by n(A).
- If n(A) = m and n(B) = n then n(A×B) = mn
- The number of subsets of a set of 'n' elements is 2^n
- The set of all subsets is called the Power set.
- The Power set of the set A is P(A) .
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