let A(2,1) ,B(5,3) and C (-1,3) be the vertices of the triangle ABC.find equationthe altitude AD ,CE .. equation of median BF and equation of perpendicular bisector of the side BC.
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Answer:
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Given : A(2,1) ,B(5,3) and C (-1,3) the vertices of the triangle ABC
To Find : equation of the altitude AD ,CE
equation of median BF and equation of perpendicular bisector of the side BC.
Solution:
equation of the altitude AD
AD ⊥ BC
Slope of BC = ( 3 - 3) / (-1 - 5) = 0
Slope of AD = -1/0
A = ( 2 , 1)
y - 1 = (-1/0)(x - 2)
=> 0 = -x + 2
=> x = 2
equation of the altitude AD is x = 2
Mid point of BC is ( 2 , 3) Hence
equation of perpendicular bisector of the side BC is also x = 2
Similarly CE Equation 3x + 2y = 3
Equation of BF = 2x - 9y + 17 = 0
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