Math, asked by latishagaonkar, 2 months ago

let A(2,1) ,B(5,3) and C (-1,3) be the vertices of the triangle ABC.find equationthe altitude AD ,CE .. equation of median BF and equation of perpendicular bisector of the side BC.​

Answers

Answered by SumitChaudhary4560
0

Answer:

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Answered by amitnrw
0

Given :   A(2,1) ,B(5,3) and C (-1,3)   the vertices of the triangle ABC

To Find  :  equation of the altitude AD ,CE

equation of median BF and equation of perpendicular bisector of the side BC.​

Solution:

equation of the altitude AD

AD ⊥ BC

Slope of BC  = ( 3 - 3) / (-1 - 5) = 0

Slope of AD = -1/0

A = ( 2 , 1)

y  -  1  =  (-1/0)(x - 2)

=> 0 =  -x  + 2

=> x  = 2

equation of the altitude AD  is x = 2

Mid point of BC  is ( 2 , 3)  Hence

equation of perpendicular bisector of the side BC is also x  = 2

Similarly CE Equation  3x + 2y = 3

Equation of BF = 2x - 9y + 17 = 0

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