Let A= {2,4,6,8}&B{6,8,10,12} 1) write AUB&Anb 2) wrie A-B& B-A 3) write number of subsets of AUB
Answers
Step-by-step explanation:
Given :-
A= {2,4,6,8}
B = {6,8,10,12}
To find :-
Find the following :
1) AUB
2) AnB
3) A-B
4) B-A
5) Number of Subsets of AUB
Solution :-
Given sets are :
A= {2,4,6,8}
B = {6,8,10,12}
I) AUB:-
=>{ 2,4,6,8 } U { 6,8,10,12 }
=> { 2,4,6,8,10,12 }
AUB = { 2,4,6,8,10,12 }
ii) AnB:-
=>{ 2,4,6,8 } n { 6,8,10,12 }
=> { 6,8 }
AnB = { 6,8 }
iii) A-B:-
=>{ 2,4,6,8 } - { 6,8,10,12 }
=> { 2,4}
A-B = { 2,4 }
iv) B-A:-
=> { 6,8,10,12 } - { 2,4,6,8 }
=> {10,12 }
B-A = { 10,12 }
v) Number of Subsets of AUB :-
AUB = {2,4,6,8,10,12 }
Number of elements in the set AUB = 6
We know that
If the number of elements in the set A is 'n' then the number of sub sets to A = 2^n
We have n = 6
Total number of subsets to AUB = 2⁶
=> 2×2×2×2×2×2
=> 64
Number of Subsets of AUB = 64
Answer:-
1)AUB = { 2,4,6,8,10,12 }
2)AnB = { 6,8 }
3)A-B = { 2,4 }
4)B-A = { 10,12 }
5)Number of Subsets of AUB = 64
Used formulae:-
- AUB is the set of the all elements in either A or in B or in both.
- AUB = {x:x€A or x€B}
- AnB is the set of all common elements in both sets A and B.
- AnB={x:x€A and x€B}
- A-B is the set of all elements in only the set A
- A-B ={x:x€A and x doesn't € B}
- B-A is the set of all elements in only the set B
- B-A ={x:x€B and x doesn't € A}
- If the number of elements in the set A is 'n' then the number of sub sets to A = 2^n