Question

let A=(2k/k epsilon N) & B=(2k+1/k epsilon N then A U B =​

Answer 1

Step-by-step explanation:

Hence a; < an, and so 2:~=1 a; is convergent by the comparison test. e) False. Let a2k =l/k for k =0,1,2, ..., and otherwise let an =O. Then an+l + ... + a2n = I/k, where k is defined uniquely by the property n+I :c:; 2k :c:; 2n.