Question

let a= 3x²-5x+7,b=2x-8x2+9,c=7+5x²-3x

a+b+3c​

Answer 1

Answer:

$23-6x$

Step-by-step explanation:

$a+b+3c = 3x^{2}-5x+7+2x-8x^{2} +9+3(7+5x^{2}-3x)\\\\=3(3-8+5)x^{2}+(2-5-3)x+7+9+7\\\\=-6x+23+0x^{2}$

$=23-6x$

∴ $a+b+3c$ when $a= 3x^{2} -5x+7,b=2x-8x^{2} +9,c=7+5x^{2} -3x$

$=23-6x$

Hope it is helpful