Let A = (-4,0), B = (-1,4). C and D are
points which are symmetric to points A
and B respectively with respect to y-axis,
then the area of the quadrilateral ABDC
is
Answers
Given:
Let A = (-4,0), B = (-1,4). C and D are points which are symmetric to points A and B respectively with respect to y-axis, then the area of the quadrilateral ABDC is
To find:
The area of the quadrilateral ABDC is
Solution:
From given, we have,
A = (-4, 0), B = (-1, 4).
As C and D are points which are symmetric to points A and B respectively with respect to the y-axis,
Then the values of C and D are same as the values of A and B, with opposite sign of x-axis:
C = (1, 4), D = (4, 0).
Consider the attached figure while going through the following steps.
Area of quadrilateral = (a + b)/2 h
from given, we have,
a = 2, b = 8 and h = 4.
Therefore, the area of the quadrilateral is,
Area of quadrilateral = (2 + 8)/2 × 4 = 10/2 × 4 = 5 × 4 = 20
∴ The area of the quadrilateral ABDC is 20 sq units
given the area of quadrilateral ans .20