Math, asked by alluargun630, 8 months ago

let A=(-4,0),B=(-1,4)C and D are points which are symmetrical to points A and B respectively to Y-axis then the area of quadrilateral ABCD is​

Answers

Answered by sshailshetty
1

Answer:

Step-by-step explanation:

As the point are symmetric to y-axis i.e. C(4,0) and D(1,4)

As it a trapezium, Area =  

2

1

​  

×height×sum of parallel sides

BD=2,AC=8,Height=4  

Area =  

2

1

​  

×4×(8+2)

⟹20sq.units

Answered by jaswanthnaidukolli
0

20sq.units

Step-by-step explanation:

as the point are symmetric to y-axis

i.e (4,0)and D(1,4)

as it a trapezium ,area =1/2×height×sum of parallel sides

BD=2,AC=8,height=4

area=1/2×4×(8+2)

=1/2×40=20sq.units

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