let A=(-4,0),B=(-1,4)C and D are points which are symmetrical to points A and B respectively to Y-axis then the area of quadrilateral ABCD is
Answers
Answered by
1
Answer:
Step-by-step explanation:
As the point are symmetric to y-axis i.e. C(4,0) and D(1,4)
As it a trapezium, Area =
2
1
×height×sum of parallel sides
BD=2,AC=8,Height=4
Area =
2
1
×4×(8+2)
⟹20sq.units
Answered by
0
20sq.units
Step-by-step explanation:
as the point are symmetric to y-axis
i.e (4,0)and D(1,4)
as it a trapezium ,area =1/2×height×sum of parallel sides
BD=2,AC=8,height=4
area=1/2×4×(8+2)
=1/2×40=20sq.units
Similar questions