Question

let A (4,2 ) and B (6,5 ) and c( 1,4) ​

Answer 1

Answer:

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Answer 2

Answer:

The median of AD -

$( \frac{6 + 1}{2} \frac{5 + 4}{2}) = (3.5 \: \: 4.5)$

AP : PD = 2 : 1

A (4, 2) D (3.5, 4.5)

$p( \frac{4 \times 1 +3.5 \times 2 }{2 + 1} \: \: \frac{2 \times 1 + 4.5 \times2}{2 + 1} )$

$p( \frac{11}{3} \: \: \frac{11}{3} )$

Median BE

$( \frac{4 + 1}{2} \: \: \frac{2 + 4}{2} ) = ( \frac{5}{2} \: \: 3)$

BQ : QE = 2 : 1

B (6, 5) E (2.5, 3)

$q( \frac{6 \times 1 + 2.5 \times 2}{3} \: \: \frac{5 \times 1 + 3 \times 2}{3} )$

$q( \frac{11}{3} \: \: \frac{11}{3} )$

Centroid G

$( \frac{4 + 6 + 1}{3} \: \: \frac{2 + 6 + 4}{3} ) \\ = ( \frac{11}{3} \: \: 4)$