Question

Let a = 4 and b = 3. Select from the drop-down menu to create a true statement 2ab + b2 > 3a2

Answer 1

The true statement is 3$a^{2}$ > 2ab + $b^{2}$

Step-by-step explanation:

Here, a = 4 and b = 3

∴ 2ab + $b^{2}$ = 2 × 4 × 3 +  $3^{2}$

= 24 + 9

= 33

and 3$a^{2}$ = 3 × $4^{2}$

= 3 × 16

= 48

∴ 2ab + $b^{2}$ > 3$a^{2}$

⇒ 24 < 34, is the false statement.

The true statement is 3$a^{2}$ > 2ab + $b^{2}$ .