Question

Let A = {6, 8) and B = {1,3,5)
Show that R1 = {(a, b)/abelongs toA, bbelongs toB, a-b
is an even number} is a null relation
R, = {(a, b)/aebelongs toA, bbelongstoB, a+b is odd number)
is an universal relation.​

Answer 1

Answer:

GIVEN:

Sin (A – B) = 1/2

cos(A+B)= ½

Sin (A – B) = ½

Sin (A – B) = sin 30°

(A – B) = 30°…………..(1)

[ sin 30° = ½]

And , cos(A+B)= 1/2

cos(A+B)= cos 60°

(A+B)= 60°…………..(2)

[cos 60° = ½]

On adding eq 1 & 2

A – B= 30°

A+ B= 60°

---------------------

2A = 90°

A = 90/2 =45°

A = 45°

On putting the value of A = 45° in eq 1

A – B= 30°

45° - B = 30°

45° - 30° = B

15° = B

Hence, the values of A is 45° & B is 15°.

HOPE THIS WILL HELP YOU...