Question

let A ={7,8} B={2,4,5} •Find A×B •determine range and domain of the relation R defined by R={(x,y):y= x+1,x€{0,1,2,3,4,5,6}​

Answer 1

A×B = {(7,2),(7,4),(7,5),(8,2),(8,4),(8,5)}

domain of relation :- [0,6]

range of relation :- [1,6]

Answer 2

Given,

$A={7,8};B={2,4,5}$

we have to fine $A\times B$

$A\times B={(7,2)(7,4),(7,5),(8,2)(8,4),(8,5)}$

Also given relation

$R={(x,y):y=x+1,xE{0,1,2,3,4,5,6}}$

Using $x$ values we have to find $y$ values

$x=0; y=0+1=1\\x=1;y=1+1=2\\x=2;y=2+1=3\\x=3;y=3+1=4\\x=4;y=4+1=5\\x=5;y=5+1=6\\x=6;y=6+1=7$

Therefore, $R={(0,1)(1,2)(2,3)(3,4)(4,5)(5,6)(6,7)}$

Domain $={0,1,2,3,4,5,6}$

Range $={1,2,3,4,5,6,7}$.