Question

Let A = {9, 10, 11, 12, 13} and let f: A → N be defined by f(n) = the highest prime factor of n. Find the range of f.​

Answer 1

━━━━━━━━━━━━━━━━━━━━━━━━━

$\Large\fbox{\color{purple}{QUESTION}}$

Let A = {9, 10, 11, 12, 13} and let f:

A → N be defined by f(n) = the highest prime factor of n. Find the range of f.

━━━━━━━━━━━━━━━━━━━━━━━━━

$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

➡️Given,

➡️A = {9, 10, 11, 12, 13}

➡️Now, f: A → N is defined as

➡️f(n) = The highest prime factor of n

➡️So,

➡️Prime factor of 9 = 3

➡️Prime factors of 10 = 2, 5

➡️Prime factor of 11 = 11

➡️Prime factors of 12 = 2, 3

➡️Prime factor of 13 = 13

➡️Thus, it can be expressed as

➡️f(9) = The highest prime factor of 9 = 3

➡️f(10) = The highest prime factor of 10 = 5

➡️f(11) = The highest prime factor of 11 = 11

➡️f(12) = The highest prime factor of 12 = 3

➡️f(13) = The highest prime factor of 13 = 13

➡️The range of f is the set of all f(n), where n ∈ A.

➡️Therefore,

➡️Range of f = {3, 5, 11, 13}

$\Large\mathcal\green{FOLLOW \: ME}$

$\Large\mathcal\green{FOLLOW \: ME}$━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 2

Answer:

➡Given,

➡️A = {9, 10, 11, 12, 13}

➡️Now, f: A → N is defined as

➡️f(n) = The highest prime factor of n

➡️So,

➡️Prime factor of 9 = 3

➡️Prime factors of 10 = 2, 5

➡️Prime factor of 11 = 11

➡️Prime factors of 12 = 2, 3

➡️Prime factor of 13 = 13

➡️Thus, it can be expressed as

➡️f(9) = The highest prime factor of 9 = 3

➡️f(10) = The highest prime factor of 10 = 5

➡️f(11) = The highest prime factor of

11 = 11

➡️f(12) = The highest prime factor of 12 = 3

➡️f(13) = The highest prime factor of 13 = 13

➡️The range of f is the set of all f(n), where n ∈ A.

➡️Therefore,

➡️Range of f = {3, 5, 11, 13}

Step-by-step explanation:

HOPE IT HELP YOU ✌✌