Let A = {a, b, c}, B = {b, d, e} and C = {e, f, g}, verify that (A Ո B) Ո C = A Ո (B Ո C)
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Given :-
- Let A = {a, b, c}, B = {b, d, e} and C = {e, f, g}
To find :-
- Verify that (A Ո B) Ո C = A Ո (B Ո C)
Solution :-
- Union of sets
→ The union of A and B is the set of all those element which belong either A or to B or to both A and B is known as union of sets
→ It is denoted by " A U B " (read as A union B)
- Intersection of sets
→ The intersections of A and B is a set of all those elements that belongs to both A and B is known as intersection of sets
→ It is denoted by " A Ո B " (read as A intersection B)
It is given that
- A = {a, b, c}
- B = {b, d, e}
- C = {e, f, g}
→ (A Ո B) Ո C = A Ո (B Ո C)
- LHS = (A Ո B) Ո C
→ (A Ո B) = {b} ( " b " is common in both A and B set)
→ C = {e, f, g}
→ (A Ո B) Ո C = { } -----(i)
- No element is common. It is known as empty, null or void set
- RHS = A Ո (B Ո C)
→ (B Ո C) = {e} ( " e " is common in B and C set}
→ A = {a, b, c}
→ A Ո (B Ո C) = { } -----(ii)
- Note : No element is common. It is known as empty, null or void set}
Hence,
- From (i) and (ii)
- LHS = RHS Verified
- (A Ո B) Ո C = A Ո (B Ո C)
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