Question

Let a= [aij] be a matrix of order 2 x 3 where aij=(i-j)/(i+j)and write the value of a23

Answer 1

The value of $a_{23}$ is $- \frac{1}{5}$ .

Given

Let a = [ $a_{ij}$ ] be a matrix of order 2 × 3

               Order 2 × 3 is 2 rows and 3 columns.

                    Order 2 × 3 = $\left[\begin{array}{ccc}a_{11} &a_{12} &a_{13} \\a_{21} &a_{22} &a_{23} \\\end{array}\right]$

From the given data where, $a_{ij}$ = $\frac{( i-j )}{( i+j )}$  (given)

To find the value of $a_{23}$,

                    $a_{ij}$ = $a_{23}$ = ?

            Here,   i = 2   ;  j = 3   ------> substitute the values in $a_{ij}$

                       $a_{ij}$ = $a_{23}$ = $\frac{( i-j )}{( i+j )}$  = $\frac{( 2-3 )}{( 2+3 )}$ = $\frac{(-1)}{5}$ = - $\frac{1}{5}$

Therefore, the value of $a_{23}$ is $- \frac{1}{5}$ .

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brainly.in/question/1220176